The first four ionisation energy values of an element are $191$,$578$,$872$ and $5962 \ kcal$. The number of valence electrons in the element is :-

The first ionization enthalpy of the following elements are in the order:

Consider the following ionisation reactions:

$A_{(g)} \to A^{+}_{(g)} + e^-, \ A_1$	$B_{(g)} \to B^{+}_{(g)} + e^-, \ B_1$
$B^{+}_{(g)} \to B^{2+}_{(g)} + e^-, \ B_2$	$C_{(g)} \to C^{+}_{(g)} + e^-, \ C_1$
$C^{+}_{(g)} \to C^{2+}_{(g)} + e^-, \ C_2$	$C^{2+}_{(g)} \to C^{3+}_{(g)} + e^-, \ C_3$

If the monovalent positive ion of $A$,divalent positive ion of $B$,and trivalent positive ion of $C$ have zero electrons,then which of the following is the incorrect order of the corresponding $I.E.$?

Element having highest $I.P.$ value is

The atomic numbers of vanadium $(V)$,chromium $(Cr)$,manganese $(Mn)$,and iron $(Fe)$ are $23$,$24$,$25$,and $26$ respectively. Which one of these is expected to have the highest second ionization enthalpy?

The first ionization potentials $\left( eV \right)$ of $Be$ and $B$ respectively are: